80=k(4)^2

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Solution for 80=k(4)^2 equation: 



80=k(4)^2

We move all terms to the left:

80-(k(4)^2)=0

determiningTheFunctionDomain
-k4^2+80=0

We move all terms containing k to the left, all other terms to the right

-k4^2=-80

k=-80/1

k=-80

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